In the previous article, we have discussed internal working about the HashMap and here we will discuss the internal working of LinkedHashMap in Java. As we know that, a lot of interviewers ask internal working of data structures such HashMap, TreeMap, LinkedHashMap, LinkedList etc. That is why I have brought such questions in front of you.
LinkedHashMap extends HashMap class and implements Map interface. That means LinkedHashMap has all functionality same as the HashMap either calculating index using Hashing for bucket finding. The difference between LinkedHashMap and HashMap is the LinkedHashMap has retrieval order same as insertion order.
LinkedHashMap in Java
LinkedHashMap is just an extension of HashMap as the class definition is as below
public class LinkedHashMap<K, V> extends HashMap<K, V> implements Map<K, V>
Structure of Each Node
Internally, the node of the LinkedHashMap represents as the below:
- int hash
- K key
- V value
- Node next
- Node previous
Let’s see the working of LinkedHashMap diagrammatically.
LinkedList Algorithms Interview Questions
Find and Break a Loop in a Linked list
How to Detect loop in a linked list
Find the nth node from the end of a singly linked list
Find the middle element in a linked list
How to Reverse linked list in Java
Delete given node from a singly linked list
Remove Duplicates from the Unsorted Singly Linked list
The singly linked list is palindrome without extra space
Hashing Implementation
As we have discussed the Hashing implementation of the LinkedHashMap same as the HashMap hashing implementation, we have already discussed in this article. Let’s see the following class of the Key implementations:
package com.dineshonjava.algo.map; /** * @author Dinesh.Rajput * */ public class Key { final int data = 112; private String key; public Key(String key) { super(); this.key = key; } //index = hashCode(key) & (n-1). @Override public int hashCode() { final int prime = 31; int result = 1; result = prime * result + data; result = prime * result + ((key == null) ? 0 : (key.charAt(0)+"").hashCode()); System.out.println("hashCode for key: "+ key + " = " + result); System.out.println("Index "+ (result & 15)); return result; } @Override public boolean equals(Object obj) { if (this == obj) return true; if (obj == null) return false; if (getClass() != obj.getClass()) return false; Key other = (Key) obj; if (data != other.data) return false; if (key == null) { if (other.key != null) return false; } else if (!key.equals(other.key)) return false; return true; } }
In the above code, I am taking a class Key and override hashCode() method to show different scenarios. Here, overridden hashCode() method return a calculated hashcode. The hashCode() method is used to get the hash code of an object. The hashCode() method of object class returns the memory reference of the object in integer form. But In LinkedHashMap, hashCode() is used to calculate the bucket and therefore calculate the index.
We have also overridden equals() method in the above code, equals method is used to check that 2 objects are equal or not. LinkedHashMap uses equals() to compare the key whether they are equal or not.
Bucketing and Indexing
Finding bucket in the LinkedHashMap is same as the HashMap, it uses hash code to find bucket as the following:
Let’s see the following relationship between bucket and capacity is as follows
capacity = number of buckets * load factor
If the hash code of two items is same then both items will be stored into the same bucket.
index = hashCode(key) & (n-1).
In the above formula, n is a number of buckets or the size of an array. In our example, I will consider n as default size that is 16.
Let’s see the how does LinkedHashMap work internally.
Internal Working of LinkedHashMap in Java
Step 1: Create an empty LinkedHashMap as the following
Map map = new LinkedHashMap();
The default size of LinkedHashMap is taken as 16 as the following empty array with size 16.
You can see the above image initially there is no element in the array.
Step 2: Inserting first element Key-Value Pair as the below:
map.put(new Key("Dinesh"), "Dinesh");
This step will be executed as the following:
- First, it will calculate the hash code of Key {“Dinesh”}. As we have implemented hashCode() method for the Key class, hash code will be generated as 4501.
- Calculate index by using a generated hash code, according to the index calculation formula, it will be 5.
- Now it creates a node object as the following:
{ int hash = 4501 Key key = {"Dinesh"} Integer value = "Dinesh" Node before = null Node after = null }
- This node will be placed at index 5. As of now, we are supposing there is no node present at this index because it is a very first element.
- As LinkedHashMap will provide us with the retrieval order as insertion order of elements, it needs to keep track of last inserted object. It has two references head and tail which will keep track of the latest object inserted and the first object inserted. Because it is very first node i.e. {“Dinesh”} is added then head and tail will both point to the same object.
Let’s see the following diagram of the LinkedHashMap:
Step 3: Adding another element Key-Value Pair as the below:
map.put(new Key("Anamika"), "Anamika");
This step will be executed as the following:
- First, it will calculate the hash code of Key {“Anamika”}. As we have implemented hashCode() method for the Key class, hash code will be generated as 4498.
- Calculate index by using a generated hash code, according to the index calculation formula, it will be 2.
- But, as we are inserting {“Anamika”} after {“Dinesh”}, this information must be present in form of some links.
So {“Dinesh”}.after will refer to {“Anamika”}, {“Anamika”}.before will refer to {“Dinesh”}. The head refers to {“Dinesh”} and tail refers to {“Anamika”}. Now it creates a node object as the following:{ int hash = 4498 Key key = {"Anamika"} Integer value = "Anamika" Node after = null Node before = {“Dinesh”} }
- This node will be placed at index 2. As of now, we are supposing there is no node present at this index because it is a very first element.
Let’s see the following diagram of the LinkedHashMap:
Step 4: Adding another element Key-Value Pair as the below:
map.put(new Key("Arnav"), "Arnav");
This step will be executed as the following:
- First, it will calculate the hash code of Key {“Arnav”}. As we have implemented hashCode() method for the Key class, hash code will be generated as 4498.
- Calculate index by using a generated hash code, according to the index calculation formula, it will be 2.
- {“Anamika”} will have next object as {“Arnav”}
- {“Arnav”} will have the previous object as {“Anamika”}
- The head will remain unchanged and will refer to {“Dinesh”}
- The tail will refer to latest added {“Arnav”}
Let’s see the following diagram of the LinkedHashMap:
I hope the article helped to understand the working of put() method of LinkedHashMap in java. Let’s see the LinkedHashMap’s get() method internal working as below:
LinkedHashMap’s get() method work internally
Now we will fetch a value from the LinkedHashMap using the get() method. As the following, we are fetching the data for key {“Arnav”}:
map.get(new Key("Arnav"));
As we know that LinkedHashMap and HashMap have almost the same functionality except maintaining insertion order. So fetching data from LinkedHashMap has the same steps as we have discussed in the previous article of HashMap.
This step will be executed as the following:
- First, it will calculate the hash code of Key {“Arnav”}. As we have implemented hashCode() method for the Key class, hash code will be generated as 4498.
- Calculate index by using a generated hash code, according to the index calculation formula, it will be 2.
- Go to index 2 of an array and compare the first element’s key with given key. If both are equals then return the value, otherwise, check for next element if it exists.
- In our case, it is not found as the first element and next of node object is not null.
- If next of node is null then return null.
- If next of node is not null traverse to the second element and repeat the process 3 until a key is not found or next is not null.
Hope this article is able to give much information about the internal working of LinkedHashMap in Java.
Happy Learning with DineshonJava.
In the Above example, After adding three objects now if we want to add one more object key “dummy” whose index is 5…
Now Dinesh after is pointed to dummy or Arnav after is pointed to dummy?
If Arnav after is pointed to dummy then map.get(new Key(‘dummy’)) will not search
If Dinesh after is pointed to dummy then the insertion order is lost
Could you help me here
Apart from after and before there is one pointer Next(same as hashmap in the entry object). So in this example arnav.after={dummy} and dinesh.next ={dummy} and tail will eventually point to dummy. Hope this helps.